Can you explain this 1 line of Java code to me?

Can you explain this 1 line of Java code to me?
This program has you enter a string and it counts up how many were not numbers. I understand it all except the if statement. Can you please explain that? The part compareTo(“0″) < 0 and compareTo("9") > 0 is what is confusing me.
import java.util.Scanner;
public class CountNonDigits {

public static void main(String args[]) {
Scanner input = new Scanner(System.in);

String str;
System.out.println(“Enter a string:”);
str = input.nextLine();

int count = 0;
for(int pos = 0; pos < str.length(); pos++) {
if (str.substring(pos,pos + 1).compareTo("0") < 0 || str.substring(pos,pos + 1).compareTo("9") > 0)
count++;
}

System.out.println(“Count = ” + count);
}
}

Best answer:

The if statement reads like this: if the character that is currently being looked at in the string is < "0" (a text 0) or if it is > “9″ (a text nine), then add one to the count. In otherwords, if the character is a 0-9 character then it does not add one to the count. Remember that with java, the substring takes the index of the character to start at and the character to end at, but does not include the character at the ending position.

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